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n in (-oo:+oo)
3*n+(2^2)/3 = (4/5)*n+12 // - (4/5)*n+12
3*n-((4/5)*n)+(2^2)/3-12 = 0
3*n+(-4/5)*n+(2^2)/3-12 = 0
11/5*n-32/3 = 0 // + 32/3
11/5*n = 32/3 // : 11/5
n = 32/3/11/5
n = 160/33
n = 160/33
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